Hot Air Balloon Ride In Pa
You decide to go for a ride in a hot-air balloon. You are hovering at a low altitude. (That is, you are neither accelerating upward nor downward.) The total weight of the balloon (including ita load and the hot air in it) is 21000 N.
(Take atmospheric pressure = 1 atm = 105 Pa and g = 10 m/s2.)
(a) What is the weight of the surrounding air that is displaced by the balloon?
Weightair = N *
21000 OK
(b) What is the volume of this displaced air? (Take the density of air to be 1.16 kg/m3.)
Vair =____________ m3
At the end of your ride, the balloon descends at 0.1 m/s2.
(c) Calculate the magnitude of the net force acting on the balloon.
Fnet= _________ N
Calculate the magnitude of the buoyant force acting on the balloon.
Fnet =___________ N
a) Archimedes’ Principle says that the weight of the displaced air will equal the buoyant force on the balloon.
Answer: 21000 N
b) F = m·a ──► m = F / a
ρ = m / V ──► V = m / ρ = F / (a·ρ)
V = 21000 / (10·1.16) = 1810 m³
c) Fweight = m·g ──► m = Fweight / g = 2100 kg
Fnet = m·a = (2100)(0.1) = 210 N
The buoyant force is the force due to its weight minus the net force:
Fb = Fweight – Fnet = 21000 – 210 = 20790 N
Hot Air Balloon Rides in Pennsylvania
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